4^2-(x-7)=2(2x-8)

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Solution for 4^2-(x-7)=2(2x-8) equation: 



4^2-(x-7)=2(2x-8)

We move all terms to the left:

4^2-(x-7)-(2(2x-8))=0

We add all the numbers together, and all the variables

-(x-7)-(2(2x-8))+16=0

We get rid of parentheses

-x-(2(2x-8))+7+16=0



We calculate terms in parentheses: -(2(2x-8)), so:

2(2x-8)

We multiply parentheses

4x-16

Back to the equation:

-(4x-16)



We add all the numbers together, and all the variables

-1x-(4x-16)+23=0

We get rid of parentheses

-1x-4x+16+23=0

We add all the numbers together, and all the variables

-5x+39=0

We move all terms containing x to the left, all other terms to the right

-5x=-39

x=-39/-5

x=7+4/5

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